[N8McGurk]

Hello,

I am using a VEVOR model AT1-220X inverter for use with a VEVOR JST-JGF-2.2KW-ER20 spindle motor (220V, 400Hz, 7.8A). The setup process wasn't too bad, and I am able to run the motor up until it reaches about 10Hz, at which point it throws "Error 01" which is listed as "short circuit / current overload / power module protection." I've already checked to make sure there are no shorts, and the wiring is correct for U/V/W between the VFD output and the motor.

I've tried playing with every parameter I can, and nothing seems to be fixing the problem. I even got a replacement motor, thinking that the first one must have been faulty, and the problem still occurs. As it stands, I am primarily concerned about parameter P67 - Voltage Coefficient and P76 - Current Coefficient. The manual lists the default for P67 as 28500 and P76 as 28000, but there is no explanation of what these values mean. Does anyone have experience with a problem like this, or at least know how I can find out what my voltage/current coefficients should be?

I'm an optics guy and this entire topic is new to me, so sorry if this is a silly question. I'd greatly appreciate any help you can provide.

Thanks,
Nate

[joeavaerage]

Hi,
the most common fault is that when a VFD leaves the factory it is set to a default of full output voltage at 50Hz or 60Hz depending on your country.
That would be fine for a regular induction motor. They run normally at full voltage, say 220V at 50 hz.

Your spindle however is supposed to run at full voltage but at 400Hz. If you do not reprogram the VFD V/F (voltage to frequency) curve to match the spindle the VFD will attempt to
apply 220V while at only 50Hz or 60Hz which will lead to a dramatic over current event. DON'T DO IT.....YOU'LL BLOW THE SPINDLE OR THE VFD OR BOTH.

I have not programmed a Vevor VFD, but I have programmed plenty of Delta VFDs, including an 11kW 400V one for my new spindle.

I programmed it to suit my spindle:

2000rpm or 66.66Hz (being a four pole motor) at 38V
10000rpm or 333.333Hz at 200V
21000rpm or 700Hz at 400V
40000rpm or 1333.33 Hz at 400V

As you can see when I say it is a V/F curve, it is a multipoint curve.
I don't like my spindle to go really really slow, they tend to overheat, that is why I have a minimum speed of 2000rpm (66.666Hz).
The manufacturer of the spindle nominated 10000rpm (333.33Hz) to be 'rated speed' and that 200V be applied at the frequency.
The manufacture also specified that full voltage (400V) can be applied at 21000rpm (700Hz). Above 21000rpm the full voltage is applied up to the maximum speed of 40000rpm (1333.333Hz)

Most V/F curves are simpler.

You could get away with:
6rpm (0.1Hz for a two pole motor) 0.5V
24000rpm (400Hz) 220V

So the V/F curve would just be a straight line, from zero (or near to it) up to max voltage at max frequency.
In the attached pic I have sketched a V/F curve that might be suitable for your spindle. Note also I include a data point of 50Hz, and that the VFD with this programming will apply 27.5V to the motor.
As the frequency increases it will apply more voltage, this is normal and how VFDs work.


I don't know what parameters Vevor use, but ultimately there must be some parameters that describe the V/F curve, its fundamental to all VFDs. You need to find them.

[joeavaerage]

Hi,
this is the first page of parameters....you cant say they are hidden.

P0=220V
P1=400Hz
P2=110V
P3=200Hz

Note that this is where I suspect you are going wrong. If you leave P2 and P3 at factory defaults the VFD will try to apply 110V at only 25Hz....and that is what will bugger it up, you want 110V, ie 1/2 the voltage
at half the frequency ie 200Hz NOT 25Hz!!!!

P6=400Hz
P7= 120Hz

Again note I have suggested a minimum speed of 120 Hz or 7200rpm....or you risk your spindle. Your choice.

Vevor might be cheap, but next time consider a better quality VFD like Delta or Hitachi.

Craig