C code question on Fagor 8055

We are trying to cut a piece that makes sort of a squarish design. It is set into 4 quadrants, each of them go from a height of .090 inch to .050 inch and then back . (I am attaching a photo to show you APPX what we are looking for). Now, I have the program that we have at the moment. What this will do, is cut the TOP (or bottom Im not really sure) 90 degrees of the piece with this design (the second photo shows what it is doing). What I want to do, is have the C axis rotate 90 degrees and then repeat the pattern 3 more times so it gets the design of the top photo. Any thoughts

%3MM 4F TEST,MX,
(ORGX54 = .325,ORGZ54 = 1.625)
;
G54
G95 G97 G40 T505 M4 ;(CUTOFF)
G0 X.5 S1500 ;M8
G0 Z0
G1 X-.06 F.0015
G0 X.5
G0 Z2.0
;
M1
;
G54
T101 ;(OD PROFILE)
G0 X.18 S1200
G0 Z.15
G1 Z.05 F.0075
G1 Z0 F.003
G1 Z-.178
G0 X.2
G0 Z2.0
;
M1
;
G54
T404 ;(ID)
G0 X0 S1000
G0 Z.5
G1 Z0 F.0075
G1 Z-.178 F.0015
G0 X-.01
G0 Z.3
G0 Z1.5
;
M1
;
(P100 = 0);START
(P102 = -.178);END
(P104 = .002);INCREMENT
;
(P110 = 45.0);START ANGLE
(P112 = 315.0);END ANGLE
;
(P106 = P100 - P104)
;
G54
G0 G90 G40 G7 T101 ;(OD PROFILE
G15
G0 X.20
G0 Z.05
G0 ZP100 C0
G51 A250 E.001
N10 G0 X.20 ZP106 C0.0
G0 X.18 CP110 F10000.0
G1 G94 X.10 C180.0
G1 X.18 CP112
(P106 = P106 - P104)
(IF P106 GT P102 GOTO N10)
G4
G0 X.2
G0 G7 Z1.0
M5
;
N20 M1
;
G54
T505 ;(CUTOFF)
G0 X.6 F.0015 S1500 M4
G0 Z0
G0 Z-.12
G0 G91 Z-.0585
G1 G90 G95 X-.06
G0 X.6 M9
G0 Z3.5
G53
M30