Can someone please clarify for me, the proper way to figure out what size power supply I will need. I am purchasing the following steppers and plan on wiring them in parallel:
3 Keling NEMA 34 Steppers Model KL34H280-45-8A When wired in a Bipolar parallel connection the specs show these as being 6.3A per phase with a 2.2mH phase inductance.
1 Keling NEMA 34 Stepper Model KL34H295-43-8A When wired in a Bipolar parallel connection the specs show these as being 6.1A per phase with a 3.3mH phase inductance.
I understand when wiring a 4 phase motor in a bipolar connection, you essentially end up with 2 phases. My question is when using the standard 2/3 current rule I keep reading about, how does the current rating work? What I mean is do I add up the current rating of all 8 phases or is it the average current rating per motor? Which one of these is correct?
(6.3+6.3)+(6.3+6.3)+(6.3+6.3)+(6.1+6.1)=50A * .67 =33.5A Needed from power supply
--or--
6.3+6.3+6.3+6.1=25A * .67 = 16.75A Needed from power supply
I think I've got the voltage formula down which I found to be √Inductance *32=Voltage Needed
I'm assuming that since the H295 motor has the highest inductance rating I should use that to figure out the voltage required, therefore:
√3.3 * 32= 58.1 V Required (or whatever standard rating is closest like 60V) Is this correct?
I know these may be dumb questions but for some reason I'm just really stumped by this one. I appreciate any and all help.