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  1. #1
    Join Date
    Nov 2012
    Posts
    139

    Geo Correction

    When I set a Geo correction table, does that affect everything, including jogging? If so, will it update the position readouts to reflect the table, or will it generally jog the other axis to keep things orthogonal?

    Also I'm trying to figure out the format of the table. Here's the example in the manual.

    2,2 (Table Size)
    1,1 (Grid Size)
    -0.5,-0.5 (What's this?)
    0,0,-1, 0, 0 (grid corrections)
    0,1, 0,-1, 0
    1,0, 0, 1, 0
    1,1, 1, 0, 0

    Thanks for any help

  2. #2
    Join Date
    May 2006
    Posts
    4043
    Hi John,

    The Geocorrection works in a similar manner as non-linear kinematics. There is a mapping between CAD Space (KMotionCNC DROS, GCode, and Jogging Directions) and Actuator Space (KFLOP Axis/Motor positions). So yes as you Jog in the X direction the tool should move in the X direction and the DROS should show motion in the X Direction. The actual Axis/Motor positions as shown in the KMotion Axis Screen will show adjusted/corrected/mapped positions.

    As you can imagine this is fairly complicated as a simple Jog in the X direction results in jogging in multiple motor axes. This is all computed a few times per second under Windows and may result in small errors while moving and changing directions, but the final position should be exact.

    Regarding "What's this?": it is the Table Offset. The CAD Space needs to properly map to the Row and Column values in the Table. On some Machines the working CAD (Machine Coordinates) might range from 0.0 to 20.0 inches in X and from 0.0 to 10.0 inches in Y. On other machines the Machine Coordinates might range from -10.0 to +10.0 inches in X and from -5.0 to +5.0 inches in Y. The Offset is how much the CAD space origin must shift to be moved to the row=0 column=0 Table point.

    In the example shown in the manual there are 4 points in the table (2 rows and 2 columns) forming a 1 inch square CAD Space with the origin in the center of the square. Therefore a shift of -0.5 -0.5 is required to move the origin from the center to the lower left point.

    HTH
    Regards
    TK
    http://dynomotion.com

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