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  1. #1
    Hello everybody,
    I want to turn an ellipse on our EMCO E45 lathe. (each with an inner and outer contour)

    Does anybody know if that’s possible and it is how it’s been done?
    Many thanks and greetings
    Ivan

  2. #2
    Hello,

    You can do almost everything with the machine and the controller. However without a drawing or sketch it’s difficult.
    Greetings from the mountains.

  3. #3
    here are the sketches for the inner and outer contour...

    [attachment=8629:ellipse_aussen.JPG]
    [attachment=8630:ellipse_innen.JPG]

  4. #4
    Join Date
    Sep 2002
    Posts
    1950
    I would try it like this:

    Set the neutral point to the centre of the ellipse (trans….)
    Trans….
    ASCALE Z=40.054 / 23.5
    g1 z0 x23.5
    g2 z21.708 x9 i-23.5

    And in the other case
    trans...
    ASCALE Z= 31 / 21
    g1 z0 x21
    g2 z21 x0 i-21

    It’s not tested!

  5. #5
    I tried but I get the following error description:

    14040 channel 1 Set endpoint of circle error
    The cursor stands then on the set: G1 Z0 X23.5

    coangry.gif

  6. #6
    Join Date
    Sep 2002
    Posts
    1950
    I tried but I get the following error description:

    14040 channel 1 Set endpoint of circle error
    The cursor stands then on the set: G1 Z0 X23.5

    coangry.gif

    Possible causes for the error could be:
    G18 is not activated ( I counted on G18 to be activated)
    The diameter programming is active (DIAMON instead of DIAMAOF)

    Another possibility: the controller has a bigger resolution than 3 ractional digits .
    Then you have to enter Z more detailed. Instead of 21.708 it’s then 21.70829335...

    I tried it out with my machine and it worked....

  7. #7
    I had to enter DIAMOF. Thanks a lot!
    How does your program looks like? I never done ISO programming on the EMCO, only via Shopturn.
    Mine looks like this:

    ;_N_1001_MPF
    G0 G53 X280 Z250 D0
    G96 S200
    DIAMOF
    T2 D1 M6
    G0 G42 X-1.5 Z1 M3
    G1 X0 Z0 F0.2 M8
    TRANS X0 Z0
    ASCALE Z=40.054 / 23.5
    G1 Z0 X23.5
    G3 Z-21.708 X9 I-23.5
    M30

    And another question: why is the Z value 21.708? Endpoint is on 37?

  8. #8
    Join Date
    Sep 2002
    Posts
    1950
    And another question: why is the Z value 21.708? Endpoint is on 37?
    I calculated it like the following method:
    The basic form of a circle with the radius 23.5, that ends at X9.
    Then is Z= SQRT(23.5 * 23.5 - 9 *9)) = 21.708

    This circle is then stretched on the Z axle by the factor 40.054 / 23.5.
    Then you arrive at the endpoint that is 37.
    You could have calculated the Z end point of the circle also like this:
    37 * 23.5 / 40.054 = 21.708

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