Hi,
Can anybody help with an algorithm for generating circular interpolation for ARCs? I know the arc center (X,Y) the radius and the start angle and the end angle.
I want to output either a G02 or G03 gcode line.
TIA,
-James Leonard
'
Hi,
Can anybody help with an algorithm for generating circular interpolation for ARCs? I know the arc center (X,Y) the radius and the start angle and the end angle.
I want to output either a G02 or G03 gcode line.
TIA,
-James Leonard
'
James Leonard - www.DragonCNC.com - www.LeonardCNCSoftware.com - www.CorelDRAWCadCam.com - www.LeonardMusicalInstruments.com
Are you just looking for a formula to find the start and endpoints? That's all you'll need to write G2 or G3 code.
Gerry
UCCNC 2017 Screenset
http://www.thecncwoodworker.com/2017.html
Mach3 2010 Screenset
http://www.thecncwoodworker.com/2010.html
JointCAM - CNC Dovetails & Box Joints
http://www.g-forcecnc.com/jointcam.html
(Note: The opinions expressed in this post are my own and are not necessarily those of CNCzone and its management)
James Leonard - www.DragonCNC.com - www.LeonardCNCSoftware.com - www.CorelDRAWCadCam.com - www.LeonardMusicalInstruments.com
You just need to find the start and endpoints using trig. I and J are the center point relative to the start point. From the little research I just did, arcs are always CCW in a dxf. It looks like you'd take the sine of the start angle times the radius will give you the Y value of the start point (relative to the center of the arc). for the X, take the sine of 90°- start angle times the radius (again relative to the center of the arc). You probably need to convert the angles from (or to) radians.
Your previous line of code needs to get you to the start point. Do the same thing to find the endpoint, which is the X,Y in your G2/G3 line.
I wrote an AutoCAD macro that outputs g-code, but it doesn't do arcs. But It will do G2 and G3 from polyline arcs. A polyline gives you the start and end points, and radius (bulge) but not the center. I find the center using a chord, and the rest is easy.
Gerry
UCCNC 2017 Screenset
http://www.thecncwoodworker.com/2017.html
Mach3 2010 Screenset
http://www.thecncwoodworker.com/2010.html
JointCAM - CNC Dovetails & Box Joints
http://www.g-forcecnc.com/jointcam.html
(Note: The opinions expressed in this post are my own and are not necessarily those of CNCzone and its management)
Hi again,
Thats good info, but I was hoping for explicit formulas. I really don't see how to calculate I and J, my math skills are not that good.
Yes, DXF ARCs are always CCW, but for CNC purposes I may need to flip them to CW. I already know how to do this and how to derive the ARC center, radius and start and end angle from three points on the ARC (begin, end and middle) but I still don't see how to do the G02 / G03 stuff.
-James Leonard
James Leonard - www.DragonCNC.com - www.LeonardCNCSoftware.com - www.CorelDRAWCadCam.com - www.LeonardMusicalInstruments.com
Find the start point of the arc using the sin method like I said. You already know the centerpoint.
I = Centerpoint X - Startpoint X
J= Centerpoint Y - Startpoint Y
Gerry
UCCNC 2017 Screenset
http://www.thecncwoodworker.com/2017.html
Mach3 2010 Screenset
http://www.thecncwoodworker.com/2010.html
JointCAM - CNC Dovetails & Box Joints
http://www.g-forcecnc.com/jointcam.html
(Note: The opinions expressed in this post are my own and are not necessarily those of CNCzone and its management)
Here is an open source program to convert DXF to G-Code:
http://www.dakeng.com/ace.html
Here is my program to convert G-Code to DXF:
http://www.cnczone.com/forums/showth...?t=8814&page=2
Wayne Hill
Hi,
The ACE converter source code is the most difficult I have ever read. I had a LOT of trouble trying to follow the DXF load and conversion process. Also ACE won't process my DXF files (from the DXFTool for CorelDraw). So, I am trying to come to a deeper understanding of this.
-James Leonard
James Leonard - www.DragonCNC.com - www.LeonardCNCSoftware.com - www.CorelDRAWCadCam.com - www.LeonardMusicalInstruments.com
James,
Can you post a short file of the DXF format that will not work with ACE ?
Line,circle and a point.
Wayne Hill
All of these DXF files are pure LINE and ARC entities. This is to improve cutting over the many shortline segments CorelDraw generates for a polyline.
Here is a circle, ellipse, star and rectangle. Both LazyCAM and SheetCAM are very happy with these DXF files.
-James
James Leonard - www.DragonCNC.com - www.LeonardCNCSoftware.com - www.CorelDRAWCadCam.com - www.LeonardMusicalInstruments.com
Could someone post the "formula" for cutting circles or circular interpolations. Just What to put in, where it all goes, and what it means. I need to cut circles and arcs.
James
Did you get what you needed.
I'm working on a program which may be of some help.
Checkout what has been done and advise (errors, improvements, future additions) if you are interested.
Thank you!
I do have the routines under control now. My big problem was a basic misunderstanding of degrees versus radians.
-James
James Leonard - www.DragonCNC.com - www.LeonardCNCSoftware.com - www.CorelDRAWCadCam.com - www.LeonardMusicalInstruments.com
The circular interpolation commands are G02 for clockwise and G03 for counterclockwise tool travel. The commands below work on a Haas, there may be machine related differences.
G91 G03 R1. X0.5 Y0.5 Fffff is the incremental command which tells the machine to cut an arc with a radius of 1.0" from where it is to the point that is 0.5" away on both the X and Y axes. The arc path to be followed is the shortest route, i.e. the arc subtends less than 180 degrees
G91 G03 R-1. X0.5 Y0.5 Fffff is the same command but the arc path to be followed is the longest route, i.e. the arc subtends greater than 180 degrees.
G90 G03 R1. X0.5 Y0.5 Fffff is the absolute command which tells the machine to cut an arc with a radius of 1.0" from where it is to the point that is located at 0.5" on both the X and Y axes using the current Work Coordinate system. The arc path to be followed is the shortest route, i.e. the arc subtends less than 180 degrees.
G90 G03 R-1. X0.5 Y0.5 Fffff is the same command but the arc path to be followed is the longest route, i.e. the arc subtends greater than 180 degrees
G03 I0. J-0.5 tells the machine to do a full counterclockwise circle around a center that is zero distance away along the X axis and 0.5" away in the negative direction on the Y axis. It does not matter whether the command is G91 or G90 this command still generates a full circle.
It is possible to have Z motion during a circular interpolation and this depends on the choice of G91 or G90. The command G91 G02 I0. J-0.5 Z-.2 tells the machine to do a full clockwise circle about the center negative 0.5" along the Y axis and at the same time increment the Z axis down 0.2". A G90 would tell the machine to move to the position Z-.2 in the current Work Coordinate system.
An open mind is a virtue...so long as all the common sense has not leaked out.
hope this info helps.
Stu
OK I'm newbie here but i have simply solution for you.
Use simply raster algorithm it's eliminate all sin(x) cosin etc. living just simply adding etc. simply enough to use it on microcontroler..
To calculate it you need create something in way matrix of point each step give you 1 point on matrix. And use this Midpoint circle algorithm.
you can find it on this pages >
http://www.cs.unc.edu/~mcmillan/comp...e7/circle.html
http://en.wikipedia.org/wiki/Midpoint_circle_algorithm
To calculate G02 G03 code you need have in memory last position ( point X Y where you end after last G-command that will be a start point of your arc ) and then depend from what parameters you want get data of circle ( radius R , or I J ) you calculating closed circle and then from G02 (03) you need to take end ( pre-calculate end point ) to finding point on circle when you circle need to stop. Then you need to use jump algo to jump from start point to end and when you jumping from point to point you copping this like result of your calculation and then you can start driving motors.
I hope this hellp you a bit.
Ar2uR,
Interesting.
Wayne Hill
Just a note.
This issue was settled for me and successfuly implemented quite a while ago. The problem I was having was trying to work in degrees when all the published algorithms / code I had been looking at needed radians...
-James
James Leonard - www.DragonCNC.com - www.LeonardCNCSoftware.com - www.CorelDRAWCadCam.com - www.LeonardMusicalInstruments.com