[daveanddanyelle]

Hi,
I think this is my first post on this forum, and I'm somewhat certain this is the right area for it, but if not, my apologies in advance.


I'm wiring the UB1 to make a cnc controller. It will use 4 Leadshine EM806 drives. I would like to use the enable and fault features of the EM806 with the UB1. I'm trying to decide whether I should use the Differential Control Signal or the NPN Control Signal as noted in the attachment? And possibly what pins on the UB1 I would then use for ENA+, ENA-, FLT+, and FLT-?

Any help GREATLY appreciated!

[john-100]

having a quick look at the UB1 manual
I would connect the drivers fault output +FLT to a UB1 input plus a 2K2 pull up resistor from +25V and -FLT to the UB1 input 0V/gnd


if your not using all axis outputs you may be able to connect the EM806 driver Enable inputs to the C axis outputs CD + CD- or Cs+ CS- for example if your control software will let you

As the UB1 outputs sink upto 70mA when a load is connected between +24V and an output you will need to add a 2K2 dropper resistor to limit the current into the EM806 drivers 5V enable input

john

[vrasak]

Hi,

After checking the manual. here is my thought.

The Leadshine EM stepper driver allows us to set the polarity of fault signal by software configuration. So we will follow the industrial standard. The fault or alarm output will be energized when the device is working properly. in case of fault or wire is broken or power failure, the alarm output does not energize the power.

John is correct if we connect EM input to 24V, then the resistor 2K2 is needed. But UB1 also provides 5V, connect it to 5V, so we don't need any resistor.

Both schematics A and B, the x104-x107 inputs are connected to drives fault output of each drive. Using the safety circuit, the users need to solder the solder bridges lie on the bottom side fo UB1 board.

I saw some machines both small and big have handle or nob which allows us to turn its axis while the machine is stopping. So taking out power from the motor by controlling enable or servo on the signal will allow us to turn it freely.

The schematic A, the enable signal for each drive are connected separately.
The schematic B using a single charge pump CP signal to control enable signal of each drive, saving wiring and output signal.

[ger21]

I read somewhere that if you configure the fault to be active low, that you can daisy chain the faults for all the drives into one input. Is this correct?

[john-100]

ger21

just downloaded the EM806 manual and the fault output can switch 24V at upto 20mA

I don't see why you can not daisy chain outputs if they are N/C and open in the event of a fault

john

[vrasak]

I read somewhere that if you configure the fault to be active low, that you can daisy chain the faults for all the drives into one input. Is this correct?

I saw some tips and techniques. People use a daisy chain of PNP proximity sensors. But, here is my first time for daisy chain of NPN opto or photo transistors.

From the theory, it is the same as we series diodes together. It is easy for me to conduct an experiment to see the results and effects. I would like to see how much voltage drop out for each opto and how many optos we can daisy chain for 24v input.

[ger21]

Here's what I saw. It's for AM882's, but they are very similar to EM806's.

Wiring up the Alarm output on Leadshine AM882 - Page 4

[vrasak]

As expected, the series of transistor can form an AND logic. I assume this concept will work for PNP transistor as well.

First, I tried 6 optocouplers in series connection as shown in the schematic with MB3 board. It sinks 24V input of MB3 without any sign of problems, then expanded to 8 cells. All work well.

If we take out any wire or component on the LED side of any optocoupler that will break conducting loop of series transistors. So, the input of MB3 stop working.

Notice that, there is a voltage drop 280-350mV on each transistor. So we can series them for some amount only. In this experiment, we series optocouplers up to 8 units and it works for 24v input. But I don't think it would work for 5V input because too much voltage drops out.

[daveanddanyelle]

Wow... that's very detailed and thorough. Thanks Weerasak. It's going to take me a while to digest all that...

Thanks again, and also to Gerry and John

[daveanddanyelle]

Hi All,
I had a little time to review the schematics this morning and would like to say thanks again to everyone for their input. Being newer to this, its really great to have help.

A quick question that have not understood from the beginning of this process... what does the dotted circle around the twisted pairs going to a pin represent?

[ger21]

The shield grounded at the drive.