You have to calculate that the DC will be 1.414 x Acv. There is a method of taking the required number of turns off of the secondary, they are usually wound bi-filar which means wound together so you can reduce both secondaries easily, if you do a search of this forum on this subject you should find it, which includes finding the turns/volt which you will need, otherwise I can point you to the right post.
Al
CNC, Mechatronics Integration and Custom Machine Design
“Logic will get you from A to B. Imagination will take you everywhere.”
Albert E.