motor rpm x motor pulley dia./ driven pulley dia. x bandsaw wheel dia. x 3.1416 / 12 = sfpm is this correct? I found a Atlas 912 bandsaw in almost mint condition and would like to use it for metal. Only paid $25
Motor= 1725rpm. w/ 2" pulley turning 10"pulley and the saw has 12" wheels inside. Should be 1083.8 sfpm. Will use a jackshaft with a 7" pulley to reduce to 154.8 sfpm. Or am I missing something?