I just got the go ahead at work to install an alarm system I have been working on. I have to get this right. This is all 24VDC and is being tapped into a currently installed 24VDC 2.5A PSU. Its being used in a loader but I am going to tap into it and it already has a breaker.
So basically a Photosensor will shoot a beam at a moving robot. When the beam is not broken for 30 secs the timer which receives its control voltage from the Photosensor will switch on a light stack. And finally the door saftey switch is going to be wired to interupt the +24VDC to the sensor.
I need to know where in my schematic attached do I need to put a fuse or fuses? The light stack says it needs a fuse of 1A but the current consumption is 90mA and the inrush current is 250mA.
The only other devices Im using that draws any current is the Photsensor which is this sensor that says Max output is 250Ma but I dont know if that is the normal consumption
Allen Bradley (AB) Photoswitch 42GRU-92LO | eBay
And a timer which says the power consumption is 7ma
So my questions are these.
1. Do I need to have a seperate fuse for the light stack and Sensor, and if so where in my schematic does it need to go?
2.Do I have to worry about arcing at the door saftey switch because the Photo Sensor's +24VDC voltage will be running through it?
3. What size fuse or fuses do I need for each?
4. Is my total possable current draw .5 amps?
Please help I have alot of pressure on me.