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  1. #1
    Join Date
    Aug 2003
    Posts
    327

    Converting oz/in to Watts

    Hey Guys,

    I have tried looking everywhere to convert oz/in to watts and i can not find the multiplier for it.

    Can anyone help.

    I want to know what 200 watts gives me in oz/in

    /Mikie

  2. #2
    Join Date
    Mar 2003
    Posts
    35538
    Watts = volts x amps. You can have 2 motors with the same power (watts), with a large difference in torque.
    Gerry

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  3. #3
    Join Date
    Oct 2004
    Posts
    590
    Quote Originally Posted by mikie
    Hey Guys,

    I have tried looking everywhere to convert oz/in to watts and i can not find the multiplier for it.

    Can anyone help.

    I want to know what 200 watts gives me in oz/in

    /Mikie
    You're comparing apples and oranges. A watt is a power measurement and oz-in is an energy measurement in other words a watt is energy per time and oz-in is simply energy. Oz-in would convert to joules. Watts would convert to horsepower.

  4. #4
    Join Date
    Aug 2005
    Posts
    34
    Watts is a measure of power (work) i.e. voltage x amperage, Torque x RPM. If a motor is generating 500 oz/inches with 0RPM then no work is being generated (500oz/in x 0RPM = 0). To convert torque to watts you will have to include the RPM in the conversion.

  5. #5
    Join Date
    Dec 2004
    Posts
    518
    Quote Originally Posted by ger21
    Watts = volts x amps. You can have 2 motors with the same power (watts), with a large difference in torque.
    Power is also speed x torque.

    To get Watts, speed must be expressed in radians/second. To get this: 1 rev/min * 2PI radians/rev * 1 min/60 seconds = 0.10472 rad/sec. So 1500 rpm = 1500 * 0.10472 = 157.1 rad/sec.

    Torque must be expressed in Newton-meters. To convert, note that 1 oz-inch = 0.0070616 Newton-meter. So 300 oz-in = 2.12 N-m.

    The motor will be delivering 157.1 rad/sec * 2.12 N-m or 333 Watts.

    746 Watts is 1 HP, so 333 Watts is 333/746 or 0.45 hp.

    The motor will have zero power output when stalled (rad/sec=0) and at max no load speed (output torque = 0). Peak output power will be at 1/2 the max no load speed for the given supply voltage. The difference between the input power (V*I) and output power (speed*torque), at a given speed is, for the most part, what is turned into heat (I squared R losses). A very little amount of the loss is due to internal friction and viscous losses. The ratio of output power to input power is the motor's efficiency.

    Hope I did my math right or I'll be totally embarrased!

    Lance

  6. #6
    Join Date
    Oct 2004
    Posts
    590
    Quote Originally Posted by Milo
    Watts is a measure of power (work) ...
    Technically power is not work. Power is work per unit of time, ie. joules/sec. Work is simply energy, ie. joules.

  7. #7
    Join Date
    Aug 2003
    Posts
    327
    Thanks guys,

    that is quite a bit of information, i now have to rememebr all those years of Physics.

    I will look p the specs on the units i bought and try to figure out what i can build with these units.

    /M

  8. #8
    Join Date
    Apr 2005
    Posts
    3634

  9. #9
    Join Date
    Aug 2003
    Posts
    327
    Thanks Switcher,

    some great reference material there.

    /M

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