[H500]

Thanks. I'll try them as an experiment. The noise is not noticeable on my dsp drive because I turn off the PID current control loop at standstill. My cpld drive hisses slightly at certain steps. Are your drives completely silent?

[lucas]

Due to their small physical size, I would never have expected that the inductance of chip resistors might be large enough to make a difference. In fact, I have used them in VHF and UHF circuits without giving any thought to possible inductance effects (well, in those circuits, you do have to pay attention to even the inductance of PC board traces). I'll have to take that into consideration in the future.

The parasitic inductance indeed depends on the size and contruction method, it is neglectable for normal values but becomes important for low value and bigger sizes. There is no problem with a 1K 805.
Inductance of PCB traces is just as important when switching inductive loads at 4AMps and more at +20kHz creating high power spikes.

Thanks. I'll try them as an experiment. The noise is not noticeable on my dsp drive because I turn off the PID current control loop at standstill. My cpld drive hisses slightly at certain steps. Are your drives completely silent?

The THB6064 is dead silent with those WSR resistors, the CPLD hisses also but the resistors here are normal ones. I didn't find time (and priority) to try it out on this drive.

[riphet]

I appreciate your time and attention given this.

I bought it and I'm waiting for the shipping.

I'm no expert in electronics,
probably I can not straighten the chip.

But I can change the capacitor to another value,
How much capacitance do you recommend?

I do not know exactly which relate resistance.
If you mean the resistors R6, R14, R15, R16, R17, R18 (R680).
I can perhaps also by the change WSR2.
But which are?

I do not know what I can do with the problem led alert.
How to send alert signal to pin 13 (EStop)?

I wonder how serve antirreversa diodes,
Be can add diodes to the circuit?

My doubts are multiplied exponentially. -LOL-

[lucas]

There's not very much you can do:
-The capacitor value is good, but it needs to be another type: Panasonic UF series are know to be one of the best, I'm using this one also, not cheap.
- The pins are bend and you can't correct if not done properly.
- The WSR2 is far too large, it can't replace the existing ones.
- you could change the resistor on the alert pin to a higher value (3K9 or 4K7) but bringing it out to the Estop will require major changes to obtain a reliable configuration.
- The diodes on the my THB6064 design didn't have much effect, this chip is similar so I don't think you will gain much, maybe a few degrees temperature reduction, not worthwhile to install them.

I would replace the cap and change or remove the alert resistor and try the drive with conservative settings and see how it goes.

[riphet]

- The diodes on the my THB6064 design didn't have much effect, this chip is similar so I don't think you will gain much, maybe a few degrees temperature reduction, not worthwhile to install them.

In the datasheet TB6560 or TB6600:
I do not see, if the IC has included (buildin) the diodes.
THB6064 included buildin the diodes?

Why would anyone in their h-bridge design include diodes?

Why desiden others that are not important?

Using them Prolongs transistor ?

Do not use them, gradually deteriorates transistors?
soft deterior?

Do not include a way to slowly deteriorate the circuit, so that at some point the customer having to buy another?

Exactly what happens and we're talking about?

Well I do not know much about electronics,
I read a bit, and then hise some calculations:

With 3Amp motor and 7 mH.

Time off transistor, switching transistor Output characteristics (time tf)
TB6560 is 1.0 ms = 0.000001 sec.
TB6600 is 0.5 ms = 0.0000005 sec.

The spike volt = H * A / sec.

With TB6560 = 0.007 * 3 / 0.000001 = 21,000 Volts
With TB6600 = 0.007 * 3 / 0.0000005 = 42,000 Volts

Please review these calculations, it could be a mistake.
I do not know whether that voltage is enough to make a arc.

I do not know how to calculate the duration of the peak,
I would like to know how to calculate it.
Also like to know how to calculate the peak current (ampere).
Maybe then I could choose a diode or decide not diode.
What is the best diode for this?
How as you do for deciding not to install diodes?
you, as you do?

I wish I knew.

My doubts are multiplied exponentially. -LOL-

[lucas]

Why would anyone in their h-bridge design include diodes?

Have a look in the datasheet at the current paths through the components in all modes.
You will notice that in some cases there's current flowing through the internal diodes integrated in the mosfets's. Their spec's are not really good for some chip's: not fast enough or to high VF.
This creates additional power to be dissipated.

This current will flow through the external diodes when good and fast ones are used and this will reduce the chip's heatdissipation.
There are other reasons also but heat reduction is the most important.

[riphet]

Have a look in the datasheet at the current paths through the components in all modes.
You will notice that in some cases there's current flowing through the internal diodes integrated in the mosfets's. Their spec's are not really good for some chip's: not fast enough or to high VF.
This creates additional power to be dissipated.

This current will flow through the external diodes when good and fast ones are used and this will reduce the chip's heatdissipation.
There are other reasons also but heat reduction is the most important.

Indeed in the datasheet is written:

"Note: Parasitic diodes are indicated on the designed lines. However, these are not normally used in Mixed Decay mode. "

"As shown in the figure above, an output transistor has parasitic diodes.
Normally, when the energy of the coil is drawn out, each transistor is turned ON and the power flows in the
opposite-to-normal direction; as a result, the parasitic diode is not used. However, when all the output
transistors are forced OFF, the coil energy is drawn out via the parasitic diode."

Only when transistors are forced OFF...
That's like a car makes a journey very well, only heats when turned off.

I understand that: Tturn off the last step of each half cycle,
As off twice per cycle. This is in any mode.

Or is it the case that when it passes through zero, some transistor is turned on?

My idea is not to dissipate heat, but that energy regenerating prosecute. I understand that even the existence of regenerating ohm causes heat. But at least most regenerated.

That's my idea, use the correct diodes.
But how fast is fast?
So, I'm looking to calculate the duration of the peak. And also current.

I appreciate any related information.