[dazp1976]

I would not have bought it as a kit.
I personally would have got different drivers.
With 2.5mh inductance 48v will be fine.
The issue for me is the 5.6A limit on the drivers.

When microstepping you need to increase the current setting for optimum performance.
I can't remember the site right now but is is said that you need to increase the driver current setting by 1.414 times the motor current.
This would mean 5A x 1.414 = 7.07A. So for full motor capability when microstepping the maximum 5.6A of not enough as far as I'm concerned.

[ninefinger]

... So for full motor capability when microstepping the maximum 5.6A of not enough as far as I'm concerned.

Well, the OP is converting a Sieg X2. I highly doubt that either the max speed or the max torque will ever be needed unless its being programmed for self destruct mode.

Hansw3 - you are best off direct driving the ball screws - that will keep the stepper motor in its happy place of lower RPM, which means it can develop max torque.
Also, a typical ballscrew with 0.2" lead (~5mm) coupled to that stepper motor will make enough force to break stuff if it jams and at 750rpm will still move at 150"/min which will be crazy fast on a small machine if you are just starting out.
Lastly, torque drop off at high speeds isn't that big a deal - you're not usually cutting at those speeds so no need for big torque. With direct drive you'll have lots of torque in the velocity range where it matters most, for having high accelerations.
Mike

[joeavaerage]

Hi,

When microstepping you need to increase the current setting for optimum performance.
I can't remember the site right now but is is said that you need to increase the driver current setting by 1.414 times the motor current.
This would mean 5A x 1.414 = 7.07A. So for full motor capability when microstepping the maximum 5.6A of not enough as far as I'm concerned.

This is incorrect. The current limit is effectively set by thermal considerations, once you reach the thermal limit you can't increase the current without
overheat damage.

That figure you mention is the square root of 2 and occurs in calculations involving 1/2 stepping. The sine of 45⁰ is 1/1.414
What the previous poster is referring to is an artificial means to maintain average current in a 1/2 stepping situation. That is so last century.
Modern stepper drives have way more sophisticated current management than that. Do not increase the current beyond the rated limit, in fact
setting the current at 2/3 to 3/4 of rated current will go a long way to having the motors run cooler.

Craig