[Cruiser]

With some basic number crunching i came up with 129,600 units per revolution (@rotary) would equal 10 seconds or .00019" of 25.133" circumferance which would be also equal to the resolution that i understand my IH mill is computed to have and would be very acceptable ! So with 129,600/90=1440 for units @ 1 turn of motor/encoder .... now i'm lost ! ..... my system uses step & direction altho mach has the encoder quadrature capability and i'm sure that this would be useable, i just am not sure how to figure it from here for a proper encoder count selection. But, would a 500 count @ quad 2000 be a good choice then to better my 10sec resolution target ?
edited in: or 2000 count encoder using simple step & direction hookup, is there even such a thing ?

[Al_The_Man]

But, would a 500 count @ quad 2000 be a good choice then to better my 10sec resolution target ?
edited in: or 2000 count encoder using simple step & direction hookup, is there even such a thing ?

I assumed you were using servo's, if using steppers then you probabally do not need encoders, as the resolution is decided by stepper.
BTW the correct term is 500 quad count x 4 = 2000. the term (quad)rature does not refer to the count in this context.
AFAIK Mach does not read encoder input. The feed back is to the drive.
I make it .002 per deg. for a (500/rev) 2000 counts encoder at 90:1 red.
Al.