Can someone tell me what N/m means and how to convert it to oz/in? Thanks
Can someone tell me what N/m means and how to convert it to oz/in? Thanks
The Nm is newton meters I believe. iIt is a measure of force over distance or torque. I belive that is what you want based on post being in the DIY router section.
the conversion would be as follows
1Nm = .7376 ft lbf
lbf = pound force
1 ft lbf = 12in/ft x 16 oz/ lbf
thus
1 Nm=141.6192 in oz
I would check again to make sure it is Nm and not N/m. N/m would convert to 1N = 1Kg/m(s^2)/m. This would lead towards a mass/area x time. This seems unlikely to be auseful measurment for anything other than maybe a bearing.
For future referece, you could do a google search and download a converter.
N/m is a newton meter just a metric unit of measure for torque.
1 newton meter = 8.8507458 inch pound-force
I usually use www.megaconverter.com but it seems broken right now...
Sorry you asked for in/oz not lb but someone beat me to the answer...
N/m (Newtons per meter) would not be a measure of torque. As TAB said, it would be a very unusual unit to measure anyhing in (nothing comes to mind...).Originally posted by freezer
N/m is a newton meter just a metric unit of measure for torque.
*snip*
Nm (Newtons times meters) is the metric unit for torque. I have the number 1 Nm = 141.612 oz-in, almost the same as TAB wrote.
Be sure to get your units right!
Arvid
With apologies to the original poster, I add this to motivate why it should be Force Times Distance, not Divided By.
T = F X r thus a force (N, oz, lb) times distance (m, ft, in, mi)
Torque is the cross-product (torque is a vector) of two vectors, a force F and a radius r.
Its magnitude |T| is given by:
|T| = |F| |r| sin (angle between vectors Fand r)
Its direction is perpendicular to the plane containing F and r, with positive direction conventionally defined by the right-hand rule:
"extending the fingers of your right hand in the direction of F and 'folding' it into r (through the smaller of the two angles between them), will result in your right thumb pointing in the direction of the resulting torque."
The torque created by a force of 1 1b hanging on the side of (e.g. so F will be perpendicular to r and the angle between them will be 90 so the sine will be 1, maximum torque) of a shaft of 0.25" diameter will be:
T = Fr(1) = (16oz)(0.125in) = 2 oz-in (oz TIMES in, not PER in)
or (2 oz-in)(1 lb/16 oz)(1 ft/12 in) = 1/96 pound-foots, although they
say foot-pounds.
Again, apologies. I don't know very much and when all you have is a hammer, everything begins to look like a nail.
--
Dan
Try this convertor http://www.export911.com/convert/conFac-N.htm
Steve
Another, perhaps more intuitive way to see that torque is force times distance:
Let's say you want to unscrew a nut that's stuck. Using a short wrench, you have to really make an effort (you have to apply a large force to the wrech), while with a big wrench, it's a lot easier.
So, to make the torque on the nut big enough, you need either a strong force, or a large distance to the "pivot point" of the nut.
If you set Torque = Force * distance, you can see that you can increase the torque by increasing either the force or the distance.
If you set Torque = Force / distance, the torque would get smaller with increasing distance, and so it would get more difficult to unscrew the nut the longer the wrench! And this is clearly not true.
So, Torque = Force * distance, written Nm (metric unit) or oz-in/lb-in/lb-ft (imperial units).
Arvid
Try this conversion software ; http://joshmadison.com/software/
It's very good and you can customize it for your own needs.
Mark...
If in doubt ask!