[lumberjack_jeff]

What is the formula for solving for sides of a right triangle when the area and an angle are known?

area = 10.5
angle Ɵ = 15°

area = 1/2 b*h.
tan Ɵ=h/b

therefore;
b = h/tan 15°
h = b*tan 15°

substituting the above formula for b;
10.5 = 1/2 (b*(tan 15°*b))

I get as far as
21 = (b*(tan 15°*b))

Then the algebra kicks my ass. It sucks to get old. 9th grade was a very long time ago.

[grabberr]

Here you go:

21 = tan(15) b^2

which reduces to

sqrt(21/tan(15)) = b

Have fun!

[lumberjack_jeff]

Here you go:

21 = tan(15) b^2

which reduces to

sqrt(21/tan(15)) = b

Have fun!

Outstanding. Thanks!

So the formula for finding the legs of a triangle when an angle and the area are known is;

sqrt(2a/tanƟ) = b

(Restating for the benefit of future googlers)