Hello
I’m getting technical qualification for mechanical engineering and metals technology. I have to calculate an eccentric.
Given:
F1= 60N (at the hand gear)
F2=16KN (at the workpiece)
A1=80mm (length of the hand gear)
I can move the hand gear at max. 120°. Goal is the eccentricity of the eccentric. I calculated A2=0,63mm. I think it’s the throw.
I hope someone can explain what and how I have to calculate next or whether it’s wrong already.
Greetings
Nils
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06-08-2010, 09:39 AM #1
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- Mar 2010
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06-08-2010, 10:30 AM #2
- Join Date
- Mar 2010
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- 145
It would be nice to have a rough sketch. Where does the workpiece have to be? Fastened to the hand gear? (-> regard friction)
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06-08-2010, 10:51 AM #3
- Join Date
- Mar 2010
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- 4
The gear has to be moved at 120° with power of 60N. The workpiece has to be clamped with 16KN.
Goal is the eccentricity of the eccentric therefore.
Greetings
EDIT: the picture isn’t shown, so this is the link to it. And it’s also in the attachment.
http://img32.imageshack.us/img32/5552/exzenter.png
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