[stang5197]

I need to rotate a turn table to two positions: 0° and 180°

Due to constraints in the center of the table lifting cylinders, I was going to use two linear pneumatic cylinders to rotate the table.

I am trying to find out the stroke required to rotate the table 180°. I know the distance from the center line of rotation effects the stroke (farther from center the shorter the stroke) but I don't know what the ratio or formula would be.

Any help would be appreciated.

See Attached Sketch for Clarification. The yellow pieces are the two linear air cylinders.

Linear length required to rotate table

[BillTodd]

You're not going to get a 180' turn from the cylinders in that arrangement.

You can turn 180' (or greater) with a single double acting (push-pull) cylinder (think steam train) , or if you want to avoid the potential dead-centre trap, you could use two double acting cylinders mounted at an angle acting on a single crank (think V twin engine).